2sin^2(x)+5cos(x)=2

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Solution for 2sin^2(x)+5cos(x)=2 equation:


Simplifying
2sin2(x) + 5cos(x) = 2

Multiply in2s * x
2in2sx + 5cos(x) = 2

Multiply cos * x
2in2sx + 5cosx = 2

Reorder the terms:
5cosx + 2in2sx = 2

Solving
5cosx + 2in2sx = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2in2sx' to each side of the equation.
5cosx + 2in2sx + -2in2sx = 2 + -2in2sx

Combine like terms: 2in2sx + -2in2sx = 0
5cosx + 0 = 2 + -2in2sx
5cosx = 2 + -2in2sx

Divide each side by '5osx'.
c = 0.4o-1s-1x-1 + -0.4in2o-1

Simplifying
c = 0.4o-1s-1x-1 + -0.4in2o-1

Reorder the terms:
c = -0.4in2o-1 + 0.4o-1s-1x-1

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